Bài 2 trang 164 sgk toán 5
Câu 2. Tính:
a) \(\frac{3}{10}\) : \(\frac{2}{5}\) ;
b) \(\frac{4}{7}\) : \(\frac{3}{11}\)
Bài giải:
a) \(\frac{3}{10}\) : \(\frac{2}{5}\) = \(\frac{3}{10}\) x \(\frac{5}{2}\) = \(\frac{15}{20}\) = \(\frac{3}{4}\) ;
b) \(\frac{4}{7}\) : \(\frac{3}{11}\) = \(\frac{4}{7}\) x \(\frac{11}{3}\) = \(\frac{44}{21}\) ;