Bài 3: Tìm x : a) \(\frac{2}{9}\) + x = 1; b) \(\frac{6}{7}\) - x = \(\frac{2}{3}\) ; c) x - \(\frac

Bài 3: Tìm x :

a) \(\frac{2}{9}\) + x = 1;

b) \(\frac{6}{7}\) - x = \(\frac{2}{3}\) ;

c) x - \(\frac{1}{2}\) = \(\frac{1}{4}\).

Lời Giải:

Bài 3:

 \(\frac{2}{9}\) + x = 1;

       x = 1 - \(\frac{2}{9}\)

       x = \(\frac{7}{9}\)

b)  \(\frac{6}{7}\) - x = \(\frac{2}{3}\)

          x = \(\frac{6}{7}\) - \(\frac{2}{3}\)

          x = \(\frac{4}{21}\)

c) x - \(\frac{1}{2}\) = \(\frac{1}{4}\)

         x = \(\frac{1}{4}\) + \(\frac{1}{2}\) 

         x = \(\frac{3}{4}\)