Bài 3: Tìm x : a) \(\frac{2}{9}\) + x = 1; b) \(\frac{6}{7}\) - x = \(\frac{2}{3}\) ; c) x - \(\frac
Bài 3: Tìm x :
a) \(\frac{2}{9}\) + x = 1;
b) \(\frac{6}{7}\) - x = \(\frac{2}{3}\) ;
c) x - \(\frac{1}{2}\) = \(\frac{1}{4}\).
Lời Giải:
Bài 3:
\(\frac{2}{9}\) + x = 1;
x = 1 - \(\frac{2}{9}\)
x = \(\frac{7}{9}\)
b) \(\frac{6}{7}\) - x = \(\frac{2}{3}\)
x = \(\frac{6}{7}\) - \(\frac{2}{3}\)
x = \(\frac{4}{21}\)
c) x - \(\frac{1}{2}\) = \(\frac{1}{4}\)
x = \(\frac{1}{4}\) + \(\frac{1}{2}\)
x = \(\frac{3}{4}\)